What is the solution for y^{''}-y^'=3x^2e^x ?

The solution for y^{''}-y^'=3x^2e^x is y=c_{1}e^x+c_{2}+e^xx^3-3(e^xx^2-2(e^xx-e^x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-y^'=3x^2e^x

y^{^{''}} - y^{^{'}} = 3 x^{2} e^{x}

y = c_{1} e^{x} + c_{2} + e^{x} x^{3} - 3 (e^{x} x^{2} - 2 (e^{x} x - e^{x}))

Solution steps

y^{''} (x) - y^{'} (x) = 3 x^{2} e^{x}

Solve linear ODE:

y = c_{1} e^{x} + c_{2} + e^{x} x^{3} - 3 (e^{x} x^{2} - 2 (e^{x} x - e^{x}))

y = c_{1} e^{x} + c_{2} + e^{x} x^{3} - 3 (e^{x} x^{2} - 2 (e^{x} x - e^{x}))

\frac{d}{d x} (\frac{1 + x}{2})

\int \frac{1}{( x - 9 ) x ^{2} - 18 x} d x

\frac{2}{( - x ^{3} + 9 x ) ^{4}}

\int \frac{x}{1 + x} d x

y^{^{'}} = 1 + x - y - x y, y (0) = - 1

What is the solution for y^{''}-y^'=3x^2e^x ?
The solution for y^{''}-y^'=3x^2e^x is y=c_{1}e^x+c_{2}+e^xx^3-3(e^xx^2-2(e^xx-e^x))