What is the derivative of sech(ln(x^2)) ?

The derivative of sech(ln(x^2)) is -(2sech(2ln(x))tanh(2ln(x)))/x

What is the first derivative of sech(ln(x^2)) ?

The first derivative of sech(ln(x^2)) is -(2sech(2ln(x))tanh(2ln(x)))/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (sech (ln (x^{2})))

- \frac{2 sech ( 2 ln ( x ) ) tanh ( 2 ln ( x ) )}{x}

Solution steps

\frac{d}{d x} (sech (ln (x^{2})))

Apply the chain rule:

- sech (ln (x^{2})) tanh (ln (x^{2})) \frac{d}{d x} (ln (x^{2}))

= - sech (ln (x^{2})) tanh (ln (x^{2})) \frac{d}{d x} (ln (x^{2}))

\frac{d}{d x} (ln (x^{2})) = \frac{2}{x}

= - sech (ln (x^{2})) tanh (ln (x^{2})) \frac{2}{x}

Simplify

- sech (ln (x^{2})) tanh (ln (x^{2})) \frac{2}{x} : - \frac{2 sech ( 2 ln ( x ) ) tanh ( 2 ln ( x ) )}{x}

= - \frac{2 sech ( 2 ln ( x ) ) tanh ( 2 ln ( x ) )}{x}

\int_{0}^{1} arctan (5 x + 3) d x

f (x) = \frac{2 x}{x + 2}, (2, 1)

\frac{1}{( ( s + 1 ) ^{2} + 4 )}

\int sin^{5} (t co) s^{4} t d t

\frac{d}{d x} (, x e^{y})

What is the derivative of sech(ln(x^2)) ?
The derivative of sech(ln(x^2)) is -(2sech(2ln(x))tanh(2ln(x)))/x
What is the first derivative of sech(ln(x^2)) ?
The first derivative of sech(ln(x^2)) is -(2sech(2ln(x))tanh(2ln(x)))/x