What is the sum from n=0 to infinity of (1-1/n)^n ?

The sum from n=0 to infinity of (1-1/n)^n is diverges

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sum from n=0 to infinity of (1-1/n)^n

n = 0 \sum \infty (1 - \frac{1}{n})^{n}

diverges

Solution steps

n = 1 \sum \infty (1 - \frac{1}{n})^{n}

Apply Series Divergence Test:

diverges

= diverges

\frac{d x}{d t} = \frac{3}{x}

x \to 0 - lim ((\frac{1}{2})^{\frac{1}{x}})

x \to - 3 lim (8 x^{2})

\int \frac{1}{9 x ^{3} - 2 x ^{2}} d x

y = x^{2} - 3 x + 3, (0, 3)

What is the sum from n=0 to infinity of (1-1/n)^n ?
The sum from n=0 to infinity of (1-1/n)^n is diverges