What is (\partial)/(\partial y)(yz^2) ?

The answer to (\partial)/(\partial y)(yz^2) is z^2

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(\partial)/(\partial y)(yz^2)

\frac{\partial}{\partial y} (y z^{2})

z^{2}

Solution steps

\frac{\partial}{\partial y} (y z^{2})

Treat

z

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z^{2} \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= z^{2} \cdot 1

Simplify

= z^{2}

x \to 0 lim (x^{2} cos (\frac{1}{x}))

f (x) sin (x)

\frac{d y}{d x} = \frac{( 3 x + 4 y )}{( 3 x + 4 y + 4 )}

sin (x) + \frac{7}{3} cot (x)

\int_{1}^{2} \frac{1}{3 - z} d z

What is (\partial)/(\partial y)(yz^2) ?
The answer to (\partial)/(\partial y)(yz^2) is z^2