What is the integral of (e^x)/(4-e^x) ?

The integral of (e^x)/(4-e^x) is -ln|4-e^x|+C

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integral of (e^x)/(4-e^x)

\int \frac{e ^{x}}{4 - e ^{x}} d x

- ln ∣ 4 - e^{x} ∣ + C

Solution steps

\int \frac{e ^{x}}{4 - e ^{x}} d x

Apply u-substitution

: \int - \frac{1}{u} d u

= \int - \frac{1}{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= - ln ∣ u ∣

Substitute back

u = 4 - e^{x}

= - ln ∣ 4 - e^{x} ∣

Add a constant to the solution

= - ln ∣ 4 - e^{x} ∣ + C

x \to 0 lim (\frac{sin ( x ) - 2 x}{x})

\frac{d}{d x} (\frac{x}{x - 1})

\int \frac{4 x ^{2}}{x ^{2}} d x

\int \frac{2 x ^{2} + 9 x + 2}{( x ^{2} + 1 ) ^{2}} d x

\frac{d}{d x} (\frac{y ^{2} - x ^{2}}{( x ^{2} + y ^{2} ) ^{2}})

What is the integral of (e^x)/(4-e^x) ?
The integral of (e^x)/(4-e^x) is -ln|4-e^x|+C