What is area f(x)=x^2-2x+1,g(x)=-x+3 ?

The answer to area f(x)=x^2-2x+1,g(x)=-x+3 is 9/2

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area f(x)=x^2-2x+1,g(x)=-x+3

area

f (x) = x^{2} - 2 x + 1, g (x) = - x + 3

\frac{9}{2}

Decimal Notation

4.5

Solution steps

Apply the area formula:

\int_{- 1}^{2} x^{2} - 2 x + 1 - (- x + 3) d x

Solve

\int_{- 1}^{2} x^{2} - 2 x + 1 - (- x + 3) d x : \frac{9}{2}

The area is:

= \frac{9}{2}

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What is area f(x)=x^2-2x+1,g(x)=-x+3 ?
The answer to area f(x)=x^2-2x+1,g(x)=-x+3 is 9/2