What is the tangent of f(x)=sqrt(5x),\at x=5 ?

The tangent of f(x)=sqrt(5x),\at x=5 is y= 1/2 x+5/2

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tangent of f(x)=sqrt(5x),\at x=5

tangent of

f (x) = 5 x, at x = 5

y = \frac{1}{2} x + \frac{5}{2}

Solution steps

Find the tangent point:

(5, 5)

Find the slope of

f (x) = 5 x : \frac{df ( x )}{d x} = \frac{5}{2 x}

Compute the slope of

f (x) = 5 x

x = 5 : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(5, 5) : y = \frac{1}{2} x + \frac{5}{2}

y = \frac{1}{2} x + \frac{5}{2}

\int tan (5 x) sec^{2} (5 x) d x

x - 2, x, [0, 4]

[x + (x + sin^{2} (x))^{7}]^{5}

\int x 1 + 2 x^{2} d x

\int \frac{3}{x ^{7}} d x

What is the tangent of f(x)=sqrt(5x),\at x=5 ?
The tangent of f(x)=sqrt(5x),\at x=5 is y= 1/2 x+5/2