What is (\partial)/(\partial x)(x^2yz^2) ?

The answer to (\partial)/(\partial x)(x^2yz^2) is 2xyz^2

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(\partial)/(\partial x)(x^2yz^2)

\frac{\partial}{\partial x} (x^{2} y z^{2})

2 x y z^{2}

Solution steps

\frac{\partial}{\partial x} (x^{2} y z^{2})

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y z^{2} \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= y z^{2} \cdot 2 x^{2 - 1}

Simplify

= 2 x y z^{2}

\frac{\partial}{\partial y} (2 x ln (y) - yz)

(e^{- x} - e^{5}) (e^{x} + e^{- 2})

y^{^{''}} - 2 y + y = t + 1, y (0) = 0, y^{^{'}} (0) = 0

f (x) = - \frac{2}{x}

What is (\partial)/(\partial x)(x^2yz^2) ?
The answer to (\partial)/(\partial x)(x^2yz^2) is 2xyz^2