What is the solution for 4x^2y^{''}+y=0 ?

The solution for 4x^2y^{''}+y=0 is y=c_{1}sqrt(x)+c_{2}ln(x)sqrt(x)

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4x^2y^{''}+y=0

4 x^{2} y^{^{''}} + y = 0

y = c_{1} x + c_{2} ln (x) x

Solution steps

4 x^{2} y^{''} (x) + y = 0

Solve linear ODE:

y = c_{1} x + c_{2} ln (x) x

y = c_{1} x + c_{2} ln (x) x

\int \frac{x ^{2}}{6} d x

\frac{d}{d x} (c x cos (2 x))

\int \frac{4 + 9 x}{4} d x

n = 1 \sum \infty (0.9)^{n}

25 y^{^{''}} - 15 y^{^{'}} - 4 y = 0

What is the solution for 4x^2y^{''}+y=0 ?
The solution for 4x^2y^{''}+y=0 is y=c_{1}sqrt(x)+c_{2}ln(x)sqrt(x)