What is the slope of (x^2+4)y=8 ?

The slope of (x^2+4)y=8 is -(16x)/((x^2+4)^2)

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slope of (x^2+4)y=8

slope

(x^{2} + 4) y = 8

- \frac{16 x}{( x ^{2} + 4 ) ^{2}}

Solution steps

(x^{2} + 4) y = 8

Isolate

y

for

(x^{2} + 4) y = 8 : y = \frac{8}{x ^{2} + 4}; x \neq = 2 i, x \neq = - 2 i

In order to find the slope of the function, take the derivative of

\frac{8}{x ^{2} + 4}

\frac{d}{d x} (\frac{8}{x ^{2} + 4}) = - \frac{16 x}{( x ^{2} + 4 ) ^{2}}

- \frac{16 x}{( x ^{2} + 4 ) ^{2}}

\int_{0.5}^{1.5} (\frac{1}{8} + \frac{3}{8} x) d x

\int (3 csc^{2} (4 x)) d x

\frac{d}{d v} (\frac{v}{u - v})

16 y^{^{''}} - y = 0

\frac{d}{d x} (5 x 2)