What is the integral from-27 to 1 of 1/(\sqrt[3]{x)} ?

The integral from-27 to 1 of 1/(\sqrt[3]{x)} is -12

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integral from-27 to 1 of 1/(\sqrt[3]{x)}

- 12

Solution steps

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= - \frac{27 ( - 1 ) ^{\frac{2}{3}}}{2} + \frac{3}{2}

Simplify

- \frac{27 ( - 1 ) ^{\frac{2}{3}}}{2} + \frac{3}{2} : - 12

= - 12

(2 x + 1) ln (x)

2 y d x + e^{- 3 x} d y = 0

\int \frac{x ^{2} + x - 5}{x ^{2} - 1} d x

\int \frac{5}{8 x ( x + 1 ) ^{2}} d x

\int - e^{- 2 y} + 1 d y

What is the integral from-27 to 1 of 1/(\sqrt[3]{x)} ?
The integral from-27 to 1 of 1/(\sqrt[3]{x)} is -12