What is inverse oflaplace-3 ?

The answer to inverse oflaplace-3 is -3\delta(t)

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inverse oflaplace-3

inverse laplace

- 3

- 3 δ (t)

Solution steps

L^{- 1} {- 3}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= - L^{- 1} {3}

L^{- 1} {3} : 3 δ (t)

= - 3 δ (t)

x = y^{2} - 8 y, x = 3 y - y^{2}

\int 10 x + 6 d x

y^{^{''}} - (\frac{3}{x}) y^{^{'}} - (\frac{4}{x ^{2}}) y = 0

\int (\frac{( x + 1 ) ( x - 1 )}{x}) d x

\int 22 sin^{2} (x) cos^{2} (x) d x