What is the derivative of 4e^x+3xe^x ?

The derivative of 4e^x+3xe^x is 7e^x+3e^xx

What is the first derivative of 4e^x+3xe^x ?

The first derivative of 4e^x+3xe^x is 7e^x+3e^xx

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derivative of

4 e^{x} + 3 x e^{x}

7 e^{x} + 3 e^{x} x

Solution steps

\frac{d}{d x} (4 e^{x} + 3 x e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 e^{x}) + \frac{d}{d x} (3 x e^{x})

\frac{d}{d x} (4 e^{x}) = 4 e^{x}

\frac{d}{d x} (3 x e^{x}) = 3 (e^{x} + e^{x} x)

= 4 e^{x} + 3 (e^{x} + e^{x} x)

Simplify

4 e^{x} + 3 (e^{x} + e^{x} x) : 7 e^{x} + 3 e^{x} x

= 7 e^{x} + 3 e^{x} x

4 (x + 2)^{\frac{3}{2}}

\frac{d}{d x} ((sin (x) + cos (x)) sec (x))

f (x) = 5 x + 4, at x = 1

\frac{d}{d x} (arctan (x) + arccos (x))

x \to \infty lim (4 x + 5)

What is the derivative of 4e^x+3xe^x ?
The derivative of 4e^x+3xe^x is 7e^x+3e^xx
What is the first derivative of 4e^x+3xe^x ?
The first derivative of 4e^x+3xe^x is 7e^x+3e^xx