What is the derivative of x^3+7 ?

The derivative of x^3+7 is 3x^2

What is the first derivative of x^3+7 ?

The first derivative of x^3+7 is 3x^2

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\frac{d}{d x} (x^{3} + 7)

3 x^{2}

Solution steps

\frac{d}{d x} (x^{3} + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (7)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (7) = 0

= 3 x^{2} + 0

Simplify

= 3 x^{2}

\int \frac{144 - x ^{2}}{x} d x

\frac{d}{d x} (3 x^{2} - 6 x + 9)

\frac{\partial}{\partial x} (y - \frac{216}{x ^{2}})

tan (x)

\frac{d}{d x} ((2 x - 8) 4 (x^{2} + x + 1) 5)