What is the derivative of ln(12-x) ?

The derivative of ln(12-x) is -1/(12-x)

What is the first derivative of ln(12-x) ?

The first derivative of ln(12-x) is -1/(12-x)

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\frac{d}{d x} (ln (12 - x))

- \frac{1}{12 - x}

Solution steps

\frac{d}{d x} (ln (12 - x))

Apply the chain rule:

\frac{1}{12 - x} \frac{d}{d x} (12 - x)

= \frac{1}{12 - x} \frac{d}{d x} (12 - x)

\frac{d}{d x} (12 - x) = - 1

= \frac{1}{12 - x} (- 1)

Simplify

= - \frac{1}{12 - x}

\frac{d}{d x} (cos^{2} (ln (x^{3} + 3 x)))

\int tan^{5} (\frac{x}{2}) d x

\frac{d}{d x} (\frac{( x ^{7} )}{x ^{14} + 1})

\int ln (x^{2} + a^{2}) d x

\frac{\partial}{\partial x} (x + i y)

What is the derivative of ln(12-x) ?
The derivative of ln(12-x) is -1/(12-x)
What is the first derivative of ln(12-x) ?
The first derivative of ln(12-x) is -1/(12-x)