What is the integral of 3x^2\times 4x^4 ?

The integral of 3x^2\times 4x^4 is (12x^7)/7+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 3x^2\times 4x^4

\int 3 x^{2} \cdot 4 x^{4} d x

\frac{12 x ^{7}}{7} + C

Solution steps

\int 3 x^{2} \cdot 4 x^{4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot 4 \cdot \int x^{2} x^{4} d x

Simplify

= 12 \cdot \int x^{2} x^{4} d x

Simplify

x^{2} x^{4} : x^{6}

= 12 \cdot \int x^{6} d x

Apply the Power Rule

: \frac{x ^{7}}{7}

= 12 \cdot \frac{x ^{7}}{7}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{12 x ^{7}}{7}

Add a constant to the solution

= \frac{12 x ^{7}}{7} + C

\int 5 x^{3} e^{- x^{2}} d x

\int \frac{1}{16 x ^{2} - 9} d x

\frac{4 x + 3}{4 x - 3}

y^{^{''}} + 36 y = e^{- t}

\int (\frac{1}{x ^{9}}) d x

What is the integral of 3x^2\times 4x^4 ?
The integral of 3x^2\times 4x^4 is (12x^7)/7+C