What is the derivative of f(x)=8sqrt(1+\sqrt{x)} ?

The derivative of f(x)=8sqrt(1+\sqrt{x)} is 2/(sqrt(x)\sqrt{\sqrt{x)+1}}

What is the first derivative of f(x)=8sqrt(1+\sqrt{x)} ?

The first derivative of f(x)=8sqrt(1+\sqrt{x)} is 2/(sqrt(x)\sqrt{\sqrt{x)+1}}

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derivative of

f (x) = 8 1 + x

\frac{2}{x x + 1}

Solution steps

\frac{d}{d x} (8 1 + x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (1 + x)

Apply the chain rule:

\frac{1}{2 1 + x} \frac{d}{d x} (1 + x)

= \frac{1}{2 1 + x} \frac{d}{d x} (1 + x)

\frac{d}{d x} (1 + x) = \frac{1}{2 x}

= 8 \cdot \frac{1}{2 1 + x} \cdot \frac{1}{2 x}

Simplify

8 \cdot \frac{1}{2 1 + x} \cdot \frac{1}{2 x} : \frac{2}{x x + 1}

= \frac{2}{x x + 1}

\frac{d}{d x} (12 x^{2} + 6 x - 6)

\frac{d}{d x} (\frac{1}{x ^{27}})

x = 22 y^{2}, x = 5 y^{3}

x \to 8 lim (sec (\frac{π \cdot x}{6}))

(3 + 2 x) e^{- 3 x}

What is the derivative of f(x)=8sqrt(1+\sqrt{x)} ?
The derivative of f(x)=8sqrt(1+\sqrt{x)} is 2/(sqrt(x)\sqrt{\sqrt{x)+1}}
What is the first derivative of f(x)=8sqrt(1+\sqrt{x)} ?
The first derivative of f(x)=8sqrt(1+\sqrt{x)} is 2/(sqrt(x)\sqrt{\sqrt{x)+1}}