What is the derivative of (x-4(x+3)) ?

The derivative of (x-4(x+3)) is 2x-1

What is the first derivative of (x-4(x+3)) ?

The first derivative of (x-4(x+3)) is 2x-1

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\frac{d}{d x} ((x - 4) (x + 3))

2 x - 1

Solution steps

\frac{d}{d x} ((x - 4) (x + 3))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x - 4, g = x + 3

= \frac{d}{d x} (x - 4) (x + 3) + \frac{d}{d x} (x + 3) (x - 4)

\frac{d}{d x} (x - 4) = 1

\frac{d}{d x} (x + 3) = 1

= 1 \cdot (x + 3) + 1 \cdot (x - 4)

Simplify

1 \cdot (x + 3) + 1 \cdot (x - 4) : 2 x - 1

= 2 x - 1

\frac{d}{d x} (\frac{x + 3}{2 x + 1})

3.8 t e^{2.4 t}

\frac{\partial}{\partial x} (\frac{- k y}{x ^{2} + y ^{2}})

5 - 3 t

x^{^{'}} + 2 x = e^{- 2 t} cos (t)

What is the derivative of (x-4(x+3)) ?
The derivative of (x-4(x+3)) is 2x-1
What is the first derivative of (x-4(x+3)) ?
The first derivative of (x-4(x+3)) is 2x-1