What is the derivative of (2x)/(x^2+y^2) ?

The derivative of (2x)/(x^2+y^2) is (2(-x^2+y^2))/((x^2+y^2)^2)

What is the first derivative of (2x)/(x^2+y^2) ?

The first derivative of (2x)/(x^2+y^2) is (2(-x^2+y^2))/((x^2+y^2)^2)

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derivative of

\frac{2 x}{x ^{2} + y ^{2}}

\frac{2 ( - x ^{2} + y ^{2} )}{( x ^{2} + y ^{2} ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 x}{x ^{2} + y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{x}{x ^{2} + y ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 2 \cdot \frac{\frac{d x}{d x} ( x ^{2} + y ^{2} ) - \frac{d}{d x} ( x ^{2} + y ^{2} ) x}{( x ^{2} + y ^{2} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2} + y^{2}) = 2 x

= 2 \cdot \frac{1 \cdot ( x ^{2} + y ^{2} ) - 2 xx}{( x ^{2} + y ^{2} ) ^{2}}

Simplify

2 \cdot \frac{1 \cdot ( x ^{2} + y ^{2} ) - 2 xx}{( x ^{2} + y ^{2} ) ^{2}} : \frac{2 ( - x ^{2} + y ^{2} )}{( x ^{2} + y ^{2} ) ^{2}}

= \frac{2 ( - x ^{2} + y ^{2} )}{( x ^{2} + y ^{2} ) ^{2}}

\frac{90 t ^{2}}{t ^{2} + 150}

n = 1 \sum \infty \frac{cos ( n ) + 2}{n}

\frac{\partial}{\partial x} (3 sin (4) x^{2} y)

\frac{\partial}{\partial x} (ln (6 x yz))

x \to 8 + lim (\frac{4}{x - 8})

What is the derivative of (2x)/(x^2+y^2) ?
The derivative of (2x)/(x^2+y^2) is (2(-x^2+y^2))/((x^2+y^2)^2)
What is the first derivative of (2x)/(x^2+y^2) ?
The first derivative of (2x)/(x^2+y^2) is (2(-x^2+y^2))/((x^2+y^2)^2)