What is the derivative of ln(1+x^2) ?

The derivative of ln(1+x^2) is (2x)/(1+x^2)

What is the first derivative of ln(1+x^2) ?

The first derivative of ln(1+x^2) is (2x)/(1+x^2)

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derivative of

ln (1 + x^{2})

\frac{2 x}{1 + x ^{2}}

Solution steps

\frac{d}{d x} (ln (1 + x^{2}))

Apply the chain rule:

\frac{1}{1 + x ^{2}} \frac{d}{d x} (1 + x^{2})

= \frac{1}{1 + x ^{2}} \frac{d}{d x} (1 + x^{2})

\frac{d}{d x} (1 + x^{2}) = 2 x

= \frac{1}{1 + x ^{2}} \cdot 2 x

Simplify

\frac{1}{1 + x ^{2}} \cdot 2 x : \frac{2 x}{1 + x ^{2}}

= \frac{2 x}{1 + x ^{2}}

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What is the derivative of ln(1+x^2) ?
The derivative of ln(1+x^2) is (2x)/(1+x^2)
What is the first derivative of ln(1+x^2) ?
The first derivative of ln(1+x^2) is (2x)/(1+x^2)