What is the derivative of 9e^{1-3x} ?

The derivative of 9e^{1-3x} is -27e^{1-3x}

What is the first derivative of 9e^{1-3x} ?

The first derivative of 9e^{1-3x} is -27e^{1-3x}

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\frac{d}{d x} (9 e^{1 - 3 x})

- 27 e^{1 - 3 x}

Solution steps

\frac{d}{d x} (9 e^{1 - 3 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (e^{1 - 3 x})

Apply the chain rule:

e^{1 - 3 x} \frac{d}{d x} (1 - 3 x)

= e^{1 - 3 x} \frac{d}{d x} (1 - 3 x)

\frac{d}{d x} (1 - 3 x) = - 3

= 9 e^{1 - 3 x} (- 3)

Simplify

= - 27 e^{1 - 3 x}

y^{^{''}} + 4 y^{^{'}} + 4 y = t

\int \frac{1}{3 + ( x - 2 ) ^{2}} d x

\frac{x ^{4}}{8} + \frac{1}{4 x ^{2}}

\int_{0}^{1} ln (1 + x^{2}) d x

1 + x, 1

What is the derivative of 9e^{1-3x} ?
The derivative of 9e^{1-3x} is -27e^{1-3x}
What is the first derivative of 9e^{1-3x} ?
The first derivative of 9e^{1-3x} is -27e^{1-3x}