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Popular >

y^'+0.2*y=5

Solution

y^{^{'}} + 0.2 \cdot y = 5

Solution

y = - 5 e^{\frac{- t - c _{1}}{5}} + 25

Solution steps

y^{'} (t) + 0.2 \cdot y = 5

Solve separable ODE:

y = - 5 e^{\frac{- t - c _{1}}{5}} + 25

y = - 5 e^{\frac{- t - c _{1}}{5}} + 25

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Frequently Asked Questions (FAQ)

What is the solution for y^'+0.2*y=5 ?
The solution for y^'+0.2*y=5 is y=-5e^{(-t-c_{1})/5}+25