What is area y=6x^4-6x^2,y=3x^2 ?

The answer to area y=6x^4-6x^2,y=3x^2 is (9sqrt(6))/5

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area y=6x^4-6x^2,y=3x^2

area

y = 6 x^{4} - 6 x^{2}, y = 3 x^{2}

\frac{9 6}{5}

Decimal Notation

4.40908 \dots

Solution steps

Apply the area formula:

\int_{- \frac{3}{2}}^{\frac{3}{2}} 6 x^{4} - 9 x^{2} d x

Solve

\int_{- \frac{3}{2}}^{\frac{3}{2}} 6 x^{4} - 9 x^{2} d x : \frac{9 6}{5}

The area is:

= \frac{9 6}{5}

\frac{d ^{2} x}{d t ^{2}} + 2 \frac{d x}{d t} + 2 x = sin (2 t)

\frac{d y}{d x} = \frac{1}{2 cos ^{2} ( x )}

\frac{d y}{d x} = y (1 - 2 y)

\int_{0}^{1} x (x^{2} - 1) e^{- x^{2}} d x

\int_{0}^{3} (x) d x

What is area y=6x^4-6x^2,y=3x^2 ?
The answer to area y=6x^4-6x^2,y=3x^2 is (9sqrt(6))/5