What is (\partial)/(\partial x)(cos(2cx+act)) ?

The answer to (\partial)/(\partial x)(cos(2cx+act)) is -sin(2cx+act)*2c

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(\partial)/(\partial x)(cos(2cx+act))

\frac{\partial}{\partial x} (cos (2 c x + a c t))

- sin (2 c x + a c t) \cdot 2 c

Solution steps

\frac{\partial}{\partial x} (cos (2 c x + a c t))

Treat

c, a, t

as a constant

Apply the chain rule:

- sin (2 c x + a c t) \frac{\partial}{\partial x} (2 c x + a c t)

= - sin (2 c x + a c t) \frac{\partial}{\partial x} (2 c x + a c t)

\frac{\partial}{\partial x} (2 c x + a c t) = 2 c

= - sin (2 c x + a c t) \cdot 2 c

\frac{d}{d x} (1000 (1 - \frac{x}{60})^{2})

y^{^{'}} = 1 + \frac{y}{x}

y^{^{''}} - y = - x

\int e^{x^{- 1}} d x

y = x^{3} - 7 x^{2} + 16 x + 7, at

What is (\partial)/(\partial x)(cos(2cx+act)) ?
The answer to (\partial)/(\partial x)(cos(2cx+act)) is -sin(2cx+act)*2c