What is the integral of (x^2+2x+4) ?

The integral of (x^2+2x+4) is (x^3)/3+x^2+4x+C

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integral of (x^2+2x+4)

\int (x^{2} + 2 x + 4) d x

\frac{x ^{3}}{3} + x^{2} + 4 x + C

Solution steps

\int x^{2} + 2 x + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x + \int 2 x d x + \int 4 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 2 x d x = x^{2}

\int 4 d x = 4 x

= \frac{x ^{3}}{3} + x^{2} + 4 x

Add a constant to the solution

= \frac{x ^{3}}{3} + x^{2} + 4 x + C

\int_{\frac{x}{z}}^{1} 1 d y

- 5 e^{x + 3} + e^{1}

\frac{\partial}{\partial x} (\frac{1}{2 π} (\frac{y}{x})^{\frac{1}{2}})

\frac{d}{d x} (a e^{3 x})

s (t) = \frac{1}{5} t^{4}

What is the integral of (x^2+2x+4) ?
The integral of (x^2+2x+4) is (x^3)/3+x^2+4x+C