What is the derivative of sqrt(-2x) ?

The derivative of sqrt(-2x) is -1/(sqrt(2)\sqrt{-x)}

What is the first derivative of sqrt(-2x) ?

The first derivative of sqrt(-2x) is -1/(sqrt(2)\sqrt{-x)}

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\frac{d}{d x} (- 2 x)

- \frac{1}{2 - x}

Solution steps

\frac{d}{d x} (- 2 x)

Apply the chain rule:

\frac{1}{2 - 2 x} \frac{d}{d x} (- 2 x)

= \frac{1}{2 - 2 x} \frac{d}{d x} (- 2 x)

\frac{d}{d x} (- 2 x) = - 2

= \frac{1}{2 - 2 x} (- 2)

Simplify

\frac{1}{2 - 2 x} (- 2) : - \frac{1}{2 - x}

= - \frac{1}{2 - x}

\int \frac{1}{( x ^{2} - 1 ) ^{3}} d x

y^{^{''}} + \frac{14}{t} y^{^{'}} + \frac{42}{t ^{2}} y = 0

\frac{d ^{2}}{d x ^{2}} (3^{x})

\frac{d}{d x} (sin (e^{x^{2}}) \cdot cos (x))

\int \frac{1}{x ^{3} - 3 x ^{2}} d x

What is the derivative of sqrt(-2x) ?
The derivative of sqrt(-2x) is -1/(sqrt(2)\sqrt{-x)}
What is the first derivative of sqrt(-2x) ?
The first derivative of sqrt(-2x) is -1/(sqrt(2)\sqrt{-x)}