What is the tangent of f(x)=2sin(x),\at x=(3pi)/4 ?

The tangent of f(x)=2sin(x),\at x=(3pi)/4 is y=-sqrt(2)x+sqrt(2)+(3pi)/(2sqrt(2))

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tangent of f(x)=2sin(x),\at x=(3pi)/4

tangent of

f (x) = 2 sin (x), at x = \frac{3 π}{4}

y = - 2 x + 2 + \frac{3 π}{2 2}

Solution steps

Find the tangent point:

(\frac{3 π}{4}, 2)

Find the slope of

f (x) = 2 sin (x) : \frac{df ( x )}{d x} = 2 cos (x)

Compute the slope of

f (x) = 2 sin (x)

x = \frac{3 π}{4} : m = - 2

Find the line with slope m=

- 2

and passing through

(\frac{3 π}{4}, 2) : y = - 2 x + 2 + \frac{3 π}{2 2}

y = - 2 x + 2 + \frac{3 π}{2 2}

y^{^{'}} = sin (5 x), y (0) = 2

\frac{\partial}{\partial x} (x^{2} + y^{2} + z^{2} - 3 x yz)

(x + 1) \frac{d y}{d x} + (x + 2) y = 8 x e^{- x}

\frac{\partial}{\partial x} (5 x^{3} y z^{2})

What is the tangent of f(x)=2sin(x),\at x=(3pi)/4 ?
The tangent of f(x)=2sin(x),\at x=(3pi)/4 is y=-sqrt(2)x+sqrt(2)+(3pi)/(2sqrt(2))