What is the tangent of f(x)=2sin(x),(pi/6 ,1) ?

The tangent of f(x)=2sin(x),(pi/6 ,1) is y=sqrt(3)x+1-pi/(2sqrt(3))

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tangent of f(x)=2sin(x),(pi/6 ,1)

tangent of

f (x) = 2 sin (x), (\frac{π}{6}, 1)

y = 3 x + 1 - \frac{π}{2 3}

Solution steps

Find the slope of

f (x) = 2 sin (x) : \frac{df ( x )}{d x} = 2 cos (x)

Compute the slope of

f (x) = 2 sin (x)

(\frac{π}{6}, 1) : m = 3

Find the line with slope m=

3

and passing through

(\frac{π}{6}, 1) : y = 3 x + 1 - \frac{π}{2 3}

y = 3 x + 1 - \frac{π}{2 3}

\int 2 x e^{x^{3}} d x

x y y^{^{'}} = y - 1

e^{- \frac{7}{x ^{7}}}

y = \frac{1}{cos ^{2} ( x )}

s^{5}

What is the tangent of f(x)=2sin(x),(pi/6 ,1) ?
The tangent of f(x)=2sin(x),(pi/6 ,1) is y=sqrt(3)x+1-pi/(2sqrt(3))