What is the integral of 1/(sin^2(y)) ?

The integral of 1/(sin^2(y)) is -cot(y)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(sin^2(y))

\int \frac{1}{sin ^{2} ( y )} d y

- cot (y) + C

Solution steps

\int \frac{1}{sin ^{2} ( y )} d y

Use the common integral:

\int \frac{1}{sin ^{2} ( y )} d y = - cot (y)

= - cot (y)

Add a constant to the solution

= - cot (y) + C

\int 121 - x^{2} d x

sin (6 (t - \frac{π}{6}))

x \to - \infty lim (2 x^{5})

y = \frac{1}{x}, at x = a

\frac{\partial}{\partial x} (4 tan (x y))

What is the integral of 1/(sin^2(y)) ?
The integral of 1/(sin^2(y)) is -cot(y)+C