What is the integral of (3x-7)^9 ?

The integral of (3x-7)^9 is 1/30 (3x-7)^{10}+C

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integral of (3x-7)^9

\int (3 x - 7)^{9} d x

\frac{1}{30} (3 x - 7)^{10} + C

Solution steps

\int (3 x - 7)^{9} d x

Apply u-substitution

: \int \frac{u ^{9}}{3} d u

= \int \frac{u ^{9}}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int u^{9} d u

Apply the Power Rule

: \frac{u ^{10}}{10}

= \frac{1}{3} \cdot \frac{u ^{10}}{10}

Substitute back

u = 3 x - 7

= \frac{1}{3} \cdot \frac{( 3 x - 7 ) ^{10}}{10}

Simplify

\frac{1}{3} \cdot \frac{( 3 x - 7 ) ^{10}}{10} : \frac{1}{30} (3 x - 7)^{10}

= \frac{1}{30} (3 x - 7)^{10}

Add a constant to the solution

= \frac{1}{30} (3 x - 7)^{10} + C

\int \frac{1}{4 x ^{2} - 9} d x

\frac{d}{d x} (3 sin (x) cos (x))

f (x) = x^{- 1} - \frac{1}{x}

x \to 2 lim (x)

\frac{d}{d x} (\frac{2}{3 x - 1})

What is the integral of (3x-7)^9 ?
The integral of (3x-7)^9 is 1/30 (3x-7)^{10}+C