What is (\partial)/(\partial x)(4x^2+5y^3-3) ?

The answer to (\partial)/(\partial x)(4x^2+5y^3-3) is 8x

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(\partial)/(\partial x)(4x^2+5y^3-3)

\frac{\partial}{\partial x} (4 x^{2} + 5 y^{3} - 3)

8 x

Solution steps

\frac{\partial}{\partial x} (4 x^{2} + 5 y^{3} - 3)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 x^{2}) + \frac{\partial}{\partial x} (5 y^{3}) - \frac{\partial}{\partial x} (3)

\frac{\partial}{\partial x} (4 x^{2}) = 8 x

\frac{\partial}{\partial x} (5 y^{3}) = 0

\frac{\partial}{\partial x} (3) = 0

= 8 x + 0 - 0

Simplify

= 8 x

\frac{\partial}{\partial x} (e^{x} sin (yz))

\frac{d}{d x} (e^{- 0.3 x})

\frac{d}{d x} (3^{x} - 4)

\frac{\partial}{\partial x} (e^{x y} + x y e^{x y})

\frac{d}{d x} (\frac{a x ^{3} + b x + c}{d x ^{3} - e})

What is (\partial)/(\partial x)(4x^2+5y^3-3) ?
The answer to (\partial)/(\partial x)(4x^2+5y^3-3) is 8x