What is laplacetransform sin(7t+4) ?

The answer to laplacetransform sin(7t+4) is (sin(4)s+7cos(4))/(s^2+49)

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laplacetransform sin(7t+4)

laplace transform

sin (7 t + 4)

\frac{sin ( 4 ) s + 7 cos ( 4 )}{s ^{2} + 49}

Solution steps

L {sin (7 t + 4)}

Use Laplace Transform table:

L {sin (a t + b)} = \frac{s \cdot sin ( b ) + a \cdot cos ( b )}{s ^{2} + a ^{2}}

L {sin (7 t + 4)} = \frac{s sin ( 4 ) + 7 cos ( 4 )}{s ^{2} + 7 ^{2}}

= \frac{s sin ( 4 ) + 7 cos ( 4 )}{s ^{2} + 7 ^{2}}

= \frac{sin ( 4 ) s + 7 cos ( 4 )}{s ^{2} + 49}

\int \frac{1}{6 x + 1} d x

\int_{0}^{\frac{1}{2}} \frac{2}{1 + 4 x ^{2}} d x

y^{^{'}} = \frac{2 x ( y - 1 )}{x ^{2} + 3}

\int 19 sin^{3} (x) cos^{2} (x) d x

f (x) = \frac{6}{x ^{2}}, at x = 1

What is laplacetransform sin(7t+4) ?
The answer to laplacetransform sin(7t+4) is (sin(4)s+7cos(4))/(s^2+49)