What is the solution for y^{''}-3y^'-10y=0 ?

The solution for y^{''}-3y^'-10y=0 is y=c_{1}e^{5t}+c_{2}e^{-2t}

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y^{''}-3y^'-10y=0

y^{^{''}} - 3 y^{^{'}} - 10 y = 0

y = c_{1} e^{5 t} + c_{2} e^{- 2 t}

Solution steps

y^{''} (t) - 3 y^{'} (t) - 10 y = 0

Solve linear ODE:

y = c_{1} e^{5 t} + c_{2} e^{- 2 t}

y = c_{1} e^{5 t} + c_{2} e^{- 2 t}

\frac{1}{( 1 + x ) ^{2}}, 1

\frac{d}{d x} (5 x)

\int 4 x^{2} + 1 d x

5 x^{2} + 2 x + 3

\frac{\partial}{\partial x} (x^{2} - 4 x y + y^{2} + 6 y + 3)

What is the solution for y^{''}-3y^'-10y=0 ?
The solution for y^{''}-3y^'-10y=0 is y=c_{1}e^{5t}+c_{2}e^{-2t}