What is the integral from 0.5 to t+4 of 3 ?

The integral from 0.5 to t+4 of 3 is 3t+10.5

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integral from 0.5 to t+4 of 3

\int_{0.5}^{t + 4} 3 d x

3 t + 10.5

Solution steps

\int_{0.5}^{t + 4} 3 d x

Integral of a constant:

\int a d x = a x

= [3 x]_{0.5}^{4 + t}

Compute the boundaries:

3 t + 10.5

= 3 t + 10.5

\int_{- 1}^{3} (4 - 2 x) d x

\int_{0}^{9} k (9 - x)

\frac{d}{d x} (arctan (\frac{a ^{2} - x ^{3}}{b ^{2}}))

\frac{d}{d x} (x \cdot (x^{5} + x^{4} + 3 x + 2))

\frac{\partial ^{2}}{\partial K ( b ) \partial b} (a K (b) (b)^{a} L^{b})

What is the integral from 0.5 to t+4 of 3 ?
The integral from 0.5 to t+4 of 3 is 3t+10.5