What is the derivative of g(x)=sqrt(6x+8) ?

The derivative of g(x)=sqrt(6x+8) is 3/(sqrt(6x+8))

What is the first derivative of g(x)=sqrt(6x+8) ?

The first derivative of g(x)=sqrt(6x+8) is 3/(sqrt(6x+8))

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derivative of

g (x) = 6 x + 8

\frac{3}{6 x + 8}

Solution steps

\frac{d}{d x} (6 x + 8)

Apply the chain rule:

\frac{1}{2 6 x + 8} \frac{d}{d x} (6 x + 8)

= \frac{1}{2 6 x + 8} \frac{d}{d x} (6 x + 8)

\frac{d}{d x} (6 x + 8) = 6

= \frac{1}{2 6 x + 8} \cdot 6

Simplify

\frac{1}{2 6 x + 8} \cdot 6 : \frac{3}{6 x + 8}

= \frac{3}{6 x + 8}

\int 2 x - y d x

x^{2} y^{^{'}} + y^{^{'}} = x y

y = x^{2} + 30 x + 225, y = 17 (x + 15)

\int \frac{5 x - 2}{x ^{2} + 6 x + 8} d x

y^{^{''}} - 4 y = 6 e^{(- t)}, y (0) = 0, y^{^{'}} (0) = 0

What is the derivative of g(x)=sqrt(6x+8) ?
The derivative of g(x)=sqrt(6x+8) is 3/(sqrt(6x+8))
What is the first derivative of g(x)=sqrt(6x+8) ?
The first derivative of g(x)=sqrt(6x+8) is 3/(sqrt(6x+8))