What is the first derivative of 4x+7 ?

The first derivative of 4x+7 is 4

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derivative of 4x+7

\frac{d}{d x} (4 x + 7)

4

Solution steps

\frac{d}{d x} (4 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x) + \frac{d}{d x} (7)

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (7) = 0

= 4 + 0

Simplify

= 4

\frac{1}{s ^{4} - 9}

\frac{1}{( s + 1 ) ( s ^{2} + 5 )}

\frac{sin ( 2 x )}{e ^{x^{2}}}

\frac{d y}{d x} = \frac{y}{x} + 3 x + 5

x \to - 7 lim (- 4 x)