What is (\partial)/(\partial x)(2x^3+xy^2) ?

The answer to (\partial)/(\partial x)(2x^3+xy^2) is 6x^2+y^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(2x^3+xy^2)

\frac{\partial}{\partial x} (2 x^{3} + x y^{2})

6 x^{2} + y^{2}

Solution steps

\frac{\partial}{\partial x} (2 x^{3} + x y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{3}) + \frac{\partial}{\partial x} (x y^{2})

\frac{\partial}{\partial x} (2 x^{3}) = 6 x^{2}

\frac{\partial}{\partial x} (x y^{2}) = y^{2}

= 6 x^{2} + y^{2}

\frac{1}{x} \frac{d y}{d x} = e^{x + y}

\frac{d}{d x} (\frac{1}{2 x ln ( x ) + 1})

\int cot^{3} (x) \cdot csc^{3} (x) d x

n = 1 \sum \infty \frac{2 n !}{n ^{n}}

r (2 r + 1)

What is (\partial)/(\partial x)(2x^3+xy^2) ?
The answer to (\partial)/(\partial x)(2x^3+xy^2) is 6x^2+y^2