What is the solution for (dy)/(dt)=5(y-t^2) ?

The solution for (dy)/(dt)=5(y-t^2) is y=t^2+(2t)/5+2/25+c_{1}e^{5t}

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(dy)/(dt)=5(y-t^2)

\frac{d y}{d t} = 5 (y - t^{2})

y = t^{2} + \frac{2 t}{5} + \frac{2}{25} + c_{1} e^{5 t}

Solution steps

\frac{d y}{d t} = 5 (y - t^{2})

Solve linear ODE:

y = t^{2} + \frac{2 t}{5} + \frac{2}{25} + c_{1} e^{5 t}

y = t^{2} + \frac{2 t}{5} + \frac{2}{25} + c_{1} e^{5 t}

\int \frac{x ^{3}}{( 2 + x ^{4} ) ^{9}} d x

y^{^{'}} = 2 y - 3 e^{- t}

x \to 0 lim (sin (\frac{2}{x}))

f (x) = 2 x + x

\frac{d y}{d x} + 3 y = 18

What is the solution for (dy)/(dt)=5(y-t^2) ?
The solution for (dy)/(dt)=5(y-t^2) is y=t^2+(2t)/5+2/25+c_{1}e^{5t}