What is the derivative of y=4x^2sin(x)tan(x) ?

The derivative of y=4x^2sin(x)tan(x) is 4(2xsin(x)tan(x)+sin(x)(1+sec^2(x))x^2)

What is the first derivative of y=4x^2sin(x)tan(x) ?

The first derivative of y=4x^2sin(x)tan(x) is 4(2xsin(x)tan(x)+sin(x)(1+sec^2(x))x^2)

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derivative of

y = 4 x^{2} sin (x) tan (x)

4 (2 x sin (x) tan (x) + sin (x) (1 + sec^{2} (x)) x^{2})

Solution steps

\frac{d}{d x} (4 x^{2} sin (x) tan (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x^{2} sin (x) tan (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = sin (x) tan (x)

= 4 (\frac{d}{d x} (x^{2}) sin (x) tan (x) + \frac{d}{d x} (sin (x) tan (x)) x^{2})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (sin (x) tan (x)) = sin (x) (1 + sec^{2} (x))

= 4 (2 x sin (x) tan (x) + sin (x) (1 + sec^{2} (x)) x^{2})

y^{^{'}} = \frac{1}{t y + 2 t + y + 2}

n \to a lim (\frac{5 n}{10 n + 4})

\frac{d}{d x} (5 - cos (x))

\frac{\partial}{\partial y} (\frac{x ^{2} y - y}{x ^{2} - 2 y})

\frac{2}{( s - 2 ) ^{2}}

What is the derivative of y=4x^2sin(x)tan(x) ?
The derivative of y=4x^2sin(x)tan(x) is 4(2xsin(x)tan(x)+sin(x)(1+sec^2(x))x^2)
What is the first derivative of y=4x^2sin(x)tan(x) ?
The first derivative of y=4x^2sin(x)tan(x) is 4(2xsin(x)tan(x)+sin(x)(1+sec^2(x))x^2)