What is the derivative of sqrt(7-8x) ?

The derivative of sqrt(7-8x) is -4/(sqrt(7-8x))

What is the first derivative of sqrt(7-8x) ?

The first derivative of sqrt(7-8x) is -4/(sqrt(7-8x))

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\frac{d}{d x} (7 - 8 x)

- \frac{4}{7 - 8 x}

Solution steps

\frac{d}{d x} (7 - 8 x)

Apply the chain rule:

\frac{1}{2 7 - 8 x} \frac{d}{d x} (7 - 8 x)

= \frac{1}{2 7 - 8 x} \frac{d}{d x} (7 - 8 x)

\frac{d}{d x} (7 - 8 x) = - 8

= \frac{1}{2 7 - 8 x} (- 8)

Simplify

\frac{1}{2 7 - 8 x} (- 8) : - \frac{4}{7 - 8 x}

= - \frac{4}{7 - 8 x}

\frac{d y}{d x} = (x + y + 5)^{2}

y^{^{''}} + 2 y = - 4 x

2 e^{- t} cos (4 t)

\frac{d}{d x} (\frac{( 4 x + b )}{( c x + d )})

x y + \frac{d y}{d x} = 100 x

What is the derivative of sqrt(7-8x) ?
The derivative of sqrt(7-8x) is -4/(sqrt(7-8x))
What is the first derivative of sqrt(7-8x) ?
The first derivative of sqrt(7-8x) is -4/(sqrt(7-8x))