What is area y=x^3-9x^2+14x,y=-x^3+9x^2-14x ?

The answer to area y=x^3-9x^2+14x,y=-x^3+9x^2-14x is 407/2

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area y=x^3-9x^2+14x,y=-x^3+9x^2-14x

area

y = x^{3} - 9 x^{2} + 14 x, y = - x^{3} + 9 x^{2} - 14 x

\frac{407}{2}

Decimal

203.5

Solution steps

Apply the area formula:

\int_{0}^{7} x^{3} - 9 x^{2} + 14 x - (- x^{3} + 9 x^{2} - 14 x) d x

Solve

\int_{0}^{7} x^{3} - 9 x^{2} + 14 x - (- x^{3} + 9 x^{2} - 14 x) d x : \frac{407}{2}

The area is:

= \frac{407}{2}

n = 1 \sum \infty \frac{5 ^{n}}{6 ^{n}}

\int_{0}^{0.6} 2000 x d x

\frac{d}{d a} (tan (a) cot (a))

\frac{1}{s} + \frac{1}{s} e^{s}

- 2

What is area y=x^3-9x^2+14x,y=-x^3+9x^2-14x ?
The answer to area y=x^3-9x^2+14x,y=-x^3+9x^2-14x is 407/2