What is the derivative of 6x+sin(3x) ?

The derivative of 6x+sin(3x) is 6+cos(3x)*3

What is the first derivative of 6x+sin(3x) ?

The first derivative of 6x+sin(3x) is 6+cos(3x)*3

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\frac{d}{d x} (6 x + sin (3 x))

6 + cos (3 x) \cdot 3

Solution steps

\frac{d}{d x} (6 x + sin (3 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x) + \frac{d}{d x} (sin (3 x))

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (sin (3 x)) = cos (3 x) \cdot 3

= 6 + cos (3 x) \cdot 3

\frac{d}{d x} (\frac{1 - x ^{2}}{2 - x ^{3}})

y^{^{''}} + 4 y^{^{'}} + 30 y = 0, y (0) = 1, y^{^{'}} (0) = 0

\int sin (3 x) cos^{2} (3 x) d x

\int_{- 1}^{4} (5 x^{4} - 8 x^{3} + 6) d x

f^{^{'}} (x) = e^{x}

What is the derivative of 6x+sin(3x) ?
The derivative of 6x+sin(3x) is 6+cos(3x)*3
What is the first derivative of 6x+sin(3x) ?
The first derivative of 6x+sin(3x) is 6+cos(3x)*3