What is the solution for (dy)/(dx)+2/x y= 1/(x^2) ?

The solution for (dy)/(dx)+2/x y= 1/(x^2) is y= 1/x+(c_{1})/(x^2)

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(dy)/(dx)+2/x y= 1/(x^2)

\frac{d y}{d x} + \frac{2}{x} y = \frac{1}{x ^{2}}

y = \frac{1}{x} + \frac{c _{1}}{x ^{2}}

Solution steps

\frac{d y}{d x} + \frac{2}{x} y = \frac{1}{x ^{2}}

Solve linear ODE:

y = \frac{1}{x} + \frac{c _{1}}{x ^{2}}

y = \frac{1}{x} + \frac{c _{1}}{x ^{2}}

n \to \infty lim (\frac{2}{n})

f (x) = \frac{3 ln ( x )}{13 x ^{2}}

x n \to 2 lim ((x n)^{2} - 5 x n + 3)

\int 7 sin^{6} (x) cos^{3} (x) d x

x \to 5 lim (7)

What is the solution for (dy)/(dx)+2/x y= 1/(x^2) ?
The solution for (dy)/(dx)+2/x y= 1/(x^2) is y= 1/x+(c_{1})/(x^2)