What is the solution for (2x-y)dx+(2y-x)dy=0,y(1)=3 ?

The solution for (2x-y)dx+(2y-x)dy=0,y(1)=3 is y=(x+sqrt(-3x^2+c_{1)})/2 ,y=(x-sqrt(-3x^2+c_{1)})/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2x-y)dx+(2y-x)dy=0,y(1)=3

(2 x - y) d x + (2 y - x) d y = 0, y (1) = 3

y = \frac{x + - 3 x ^{2} + c _{1}}{2}, y = \frac{x - - 3 x ^{2} + c _{1}}{2}

Solution steps

(2 x - y) d x + (2 y - x) d y = 0

Solve exact ODE:

y = \frac{x + - 3 x ^{2} + c _{1}}{2}, y = \frac{x - - 3 x ^{2} + c _{1}}{2}

y = \frac{x + - 3 x ^{2} + c _{1}}{2}, y = \frac{x - - 3 x ^{2} + c _{1}}{2}

csc (x)

\int \frac{1 - sin ( θ )}{θ + cos ( θ )} d θ

\int e^{- x} - sin (2 x) d x

\frac{d}{d x} ((x^{6} - 2)^{3})

2 y^{^{''}} - 6 y^{^{'}} + 4 y = 6 e^{2 t}

What is the solution for (2x-y)dx+(2y-x)dy=0,y(1)=3 ?
The solution for (2x-y)dx+(2y-x)dy=0,y(1)=3 is y=(x+sqrt(-3x^2+c_{1)})/2 ,y=(x-sqrt(-3x^2+c_{1)})/2