What is the derivative of f(x)=3x^2+1 ?

The derivative of f(x)=3x^2+1 is 6x

What is the first derivative of f(x)=3x^2+1 ?

The first derivative of f(x)=3x^2+1 is 6x

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derivative of

f (x) = 3 x^{2} + 1

6 x

Solution steps

\frac{d}{d x} (3 x^{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (1) = 0

= 6 x + 0

Simplify

= 6 x

\frac{d}{d x} (ln^{3} (2 x + 5))

x y^{^{'}} + y = x^{4} y^{3}

\frac{d}{d x} ((6 x - 7)^{3} (8 x^{2} + 9)^{2})

\int_{0}^{5} (5 - x) d x

x y d y = y d x

What is the derivative of f(x)=3x^2+1 ?
The derivative of f(x)=3x^2+1 is 6x
What is the first derivative of f(x)=3x^2+1 ?
The first derivative of f(x)=3x^2+1 is 6x