What is the derivative of 2x^2-1/x ?

The derivative of 2x^2-1/x is 4x+1/(x^2)

What is the first derivative of 2x^2-1/x ?

The first derivative of 2x^2-1/x is 4x+1/(x^2)

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\frac{d}{d x} (2 x^{2} - \frac{1}{x})

4 x + \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (2 x^{2} - \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (\frac{1}{x})

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= 4 x - (- \frac{1}{x ^{2}})

Simplify

= 4 x + \frac{1}{x ^{2}}

\int_{0}^{8} 1

x \to 3 lim (x^{2} - 4 x + 10)

\int tan^{3} (5 x) sec (5 x) d x

\int \frac{x - 1}{x ^{2} + x - 6} d x

(x + y)^{2} d x + (2 x y + x^{2} - 3) d y = 0, y (1) = 1

What is the derivative of 2x^2-1/x ?
The derivative of 2x^2-1/x is 4x+1/(x^2)
What is the first derivative of 2x^2-1/x ?
The first derivative of 2x^2-1/x is 4x+1/(x^2)