What is the solution for (dy)/(dx)=((y^2+y))/(x^2+x) ?

The solution for (dy)/(dx)=((y^2+y))/(x^2+x) is y=(e^{c_{1}}x)/(x+1-e^{c_{1)}x}

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(dy)/(dx)=((y^2+y))/(x^2+x)

\frac{d y}{d x} = \frac{( y ^{2} + y )}{x ^{2} + x}

y = \frac{e ^{c_{1}} x}{x + 1 - e ^{c_{1}} x}

Solution steps

\frac{d y}{d x} = \frac{( y ^{2} + y )}{x ^{2} + x}

Solve separable ODE:

y = \frac{e ^{c_{1}} x}{x + 1 - e ^{c_{1}} x}

y = \frac{e ^{c_{1}} x}{x + 1 - e ^{c_{1}} x}

\int_{0}^{\infty} x e^{- \frac{x}{2}} d x

\int_{0}^{π} 5 e^{x} sin (x) d x

n = 1 \sum \infty 2

(\frac{x + 6}{x - 6})^{5}

\frac{d}{d x} (e^{- \frac{x}{3}})

What is the solution for (dy)/(dx)=((y^2+y))/(x^2+x) ?
The solution for (dy)/(dx)=((y^2+y))/(x^2+x) is y=(e^{c_{1}}x)/(x+1-e^{c_{1)}x}