What is area y=3x^4-3x^2,y=8x^2 ?

The answer to area y=3x^4-3x^2,y=8x^2 is (484sqrt(11))/(45sqrt(3))

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area y=3x^4-3x^2,y=8x^2

area

y = 3 x^{4} - 3 x^{2}, y = 8 x^{2}

\frac{484 11}{45 3}

Decimal

20.59532 \dots

Solution steps

Apply the area formula:

\int_{- \frac{11}{3}}^{\frac{11}{3}} 3 x^{4} - 11 x^{2} d x

Solve

\int_{- \frac{11}{3}}^{\frac{11}{3}} 3 x^{4} - 11 x^{2} d x : \frac{484 11}{45 3}

The area is:

= \frac{484 11}{45 3}

y = (2 x - 3)^{4} (x^{2} + x + 1)^{5}

\frac{d}{d x} (a^{6 x^{2}})

\int \frac{x ^{2}}{4 x} d x

x^{2} y^{^{'}} + 3 x y = e^{x}

2 y^{^{''}} - 2 y^{^{'}} + 13 y = 0

What is area y=3x^4-3x^2,y=8x^2 ?
The answer to area y=3x^4-3x^2,y=8x^2 is (484sqrt(11))/(45sqrt(3))