What is the derivative of-4sin^3(3x) ?

The derivative of-4sin^3(3x) is -36sin^2(3x)cos(3x)

What is the first derivative of-4sin^3(3x) ?

The first derivative of-4sin^3(3x) is -36sin^2(3x)cos(3x)

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\frac{d}{d x} (- 4 sin^{3} (3 x))

- 36 sin^{2} (3 x) cos (3 x)

Solution steps

\frac{d}{d x} (- 4 sin^{3} (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d x} (sin^{3} (3 x))

Apply the chain rule:

3 (sin (3 x))^{2} \frac{d}{d x} (sin (3 x))

= 3 (sin (3 x))^{2} \frac{d}{d x} (sin (3 x))

\frac{d}{d x} (sin (3 x)) = cos (3 x) \cdot 3

= - 4 \cdot 3 (sin (3 x))^{2} cos (3 x) \cdot 3

Simplify

= - 36 sin^{2} (3 x) cos (3 x)

\int \frac{1}{5000 x - x ^{2}} d x

\int_{0}^{9} 2 x + 8 - x d x

\int_{0}^{\frac{π}{4}} 1 - 4 sin^{2} (x) d x

\int 2 u sin (u) d u

\frac{d y}{d x} = \frac{x + y}{x}

What is the derivative of-4sin^3(3x) ?
The derivative of-4sin^3(3x) is -36sin^2(3x)cos(3x)
What is the first derivative of-4sin^3(3x) ?
The first derivative of-4sin^3(3x) is -36sin^2(3x)cos(3x)