What is the derivative of 3x^2+2x-1 ?

The derivative of 3x^2+2x-1 is 6x+2

What is the first derivative of 3x^2+2x-1 ?

The first derivative of 3x^2+2x-1 is 6x+2

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\frac{d}{d x} (3 x^{2} + 2 x - 1)

6 x + 2

Solution steps

\frac{d}{d x} (3 x^{2} + 2 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (2 x) - \frac{d}{d x} (1)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 6 x + 2 - 0

Simplify

= 6 x + 2

t \to 2 lim (t^{3} i + t^{4} j + t^{5} k)

\frac{\partial}{\partial x} (x^{4} + 3 x y^{2} - 3 y^{2})

\int_{0}^{4} (1 + 3 x - x^{2}) d x

\int_{- \infty}^{0} \frac{1}{3 - 10 x} d x

- 4 x^{5} + 6 x^{7}

What is the derivative of 3x^2+2x-1 ?
The derivative of 3x^2+2x-1 is 6x+2
What is the first derivative of 3x^2+2x-1 ?
The first derivative of 3x^2+2x-1 is 6x+2